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FUNDAMENTALS OF SURVEYING 2
Self-Pace Module
Module 3 PARTITION OF LAND (SUBDIVISION OF LAND)
Topics 1.Dividing an Area Into Two Parts by a Line Between Two Points
2. Dividing an Area by A Line Running Through A Point in a Given Direction
3. To Cut off a Required Area by a Line through a Given Point
4. To Cut of a Required Area by a Line Running in a Given Direction
Overview: This module will presents computations common cases encountered in
partition and subdivision of land.
Duration: Week 9-10 (2 weeks)
Targeting Learning Outcomes
Course Intended Learning
Outcomes
-Compute for the technical data of subdivided land
- Subdivide the land by given line or required area
Essential Questions Why does engineer or surveyor needs to know the process of
subdividing the land
Learning Targets At the end of this module, you should be able to learn how to subdivide
lots thru given line or required area
Reference and Credits: Elementary Surveying, by Ghilani and Wolf
Elementary Surveying by La Putt
Introduction
The subdivision of land is a usual task undertaken by surveyors and engineers in
property surveys. When tracts of land are sold or inherited it is often necessary to divide it
into smaller parcels or into areas having certain proportions to each other. The process of
subdivision may require the application of the principles of geometry and trigonometry or use
of special techniques in computations or engineering software (CAD, GE Survey, Spreadsheets
etc).
For various cases in subdividing land, a resurvey is conducted, the latitudes and
departures are determined, the surveyed traversed is adjusted and the areas are computed.
When computing for subdivision of land, the adjusted latitudes and departures are used.
CASE 1. Dividing an Area into Two Parts by a Line Between Two Points
Example: Given the following data of tract of land, determine the area of a line running from F
to C and calculate the length and bearing of line FC
Course Adj
Latitude
Adjusted
Departure
AB 490.71 47.27
BC 587.12 608.89
CD -327.41 786.78
DE -1002.76 218.32
EF -122.67 -1116.62
FA 375.01 -544.64
∑lat =0 ∑dep=0
A
F
B
C
D
E
Solution:
1. Determine the area of the whole close traverse
Course
Adj
Latitude
Adjusted
Departure
DMD Double Area
(DMD x Adj Lat.)
AB 490.71 47.27 47.27 23,195.86
BC 587.12 608.89 703.43 412,997.82
CD -327.41 786.78 2099.1 -687,266.33
DE -1002.8 218.32 3104.2 -3,112,767.59
EF -122.67 -1116.62 2205.9 -270,597.75
FA 375.01 -544.64 544.64 204,245.45
0 0 -3,430,192.55
AREA = -1,715,096.27
or -171.51 Hectares
2. Determine the length and bearing of dividing line FC (consider west section FABC)
A
F
B
C
Course Adj Latitude
Adjusted
Departure
AB 490.71 47.27
BC 587.12 608.89
FA 375.01 -544.64
Summation 1452.84 111.52
therefore length of line FC 1457.11 m
Bearing of Line FC (tan-1
∑dep/∑lat)
0.076609773 4.389417 S 4o
23' W Ans.
3. Compute for the area of FABC
Course
Adj
Latitude
Adjusted
Departure
DMD
Double Area
(DMD x Adj Lat.)
AB 490.71 47.27 47.27 23,195.86
BC 587.12 608.89 703.43 412,997.82
CF -1452.8 -111.52 1200.8 -1,744,570.27
FA 375.01 -544.64 544.64 204,245.45
0 0 -1,104,131.14
AREA FABC = -552,065.57 sq.m.
or -55.21 Hectares Ans
4. Compute bearing and length bearing of line CF using west portion CDEF
Course Adj Latitude
Adjusted
Departure
CD -327.41 786.78
DE -1002.76 218.32
EF -122.67 -1116.62
Summation -1452.84 -111.52
therefore length of line FC 1457.11 m
Bearing of Line FC (tan-1
∑dep/∑lat)
0.076609773 4.389417 N 4o
23' E Ans.
F
C
D
E
5. Compute for the area of CDEF
Course
Adj
Latitude
Adjusted
Departure
DMD
Double Area
(DMD x Adj Lat.)
CD -327.41 786.78 786.78 -257,599.64
DE -1002.76 218.32 1791.88 -1,796,825.59
EF -122.67 -1116.62 893.58 -109,615.46
FC 1452.84 111.52 -111.52 -162,020.72
0 0 -2,326,061.40
AREA CDEF = -1,163,030.70 sq.m.
or -116.30 Hectares Ans
6. Check the area of ABCDEF to sum of area CDEF and area ABCF
AREA ABCDEF = 1,715,096.27
AREA ABCF= 552,065.57 sq.m
AREA CDEF = 1,163,030.70 sq.m
1,715,096.27 sq.m. check!
CASE 2. Dividing a Tract of Land by a Line Running in a Given Direction
Example: Given the following data of tract of land, find the area of each of the two
parts into which the tract is divided by a line through A with bearing of N 75o30’ E.
Course Adj
Latitude
Adjusted
Departure
AB 490.71 47.27
BC 587.12 608.89
CD -327.41 786.78
DE -1002.76 218.32
EF -122.67 -1116.62
FA 375.01 -544.64
∑lat =0 ∑dep=0
A
F
B
C
D
E
P
Solution:
1. Determine the area of the whole close traverse
Course
Adj
Latitude
Adjusted
Departure
DMD Double Area
(DMD x Adj Lat.)
AB 490.71 47.27 47.27 23,195.86
BC 587.12 608.89 703.43 412,997.82
CD -327.41 786.78 2099.1 -687,266.33
DE -1002.8 218.32 3104.2 -3,112,767.59
EF -122.67 -1116.62 2205.9 -270,597.75
FA 375.01 -544.64 544.64 204,245.45
0 0 -3,430,192.55
AREA = -1,715,096.27
or -171.51 Hectares
2. Make a trial line AE, determine the length and bearing of line EA and area of AEF
Course
Adj.
Latitude
Adj.
Departure
EF -122.67 -1116.62
FA 375.01 -544.64
∑ 252.34 -1661.26
therefore length of AE = 1680.32 m
Bearing of Line AE (tan-1
∑dep/∑lat)
-1.42005 -81.36298 S 81o
22'E Ans
Course Adj.
Latitude
Adj.
Departur
e
DMD
Double Area
(DMD x Adj
Lat.)
EF -122.67 -1116.6 -1117 136,975.78
FA 375.01 -544.64 -2778 -1,041,732.78
EA -252.34 1661.26 -1661 419,202.35
∑ 0 0 -485,554.66
AREA EFA = -242,777.33
or -24.28 Hectares
****We will use CAD for the other computation/solution or you can refer to solutions in Elementary
Surveying by La Putt pp 503-506*****
Learning Tasks No. 3: Problems Sets in Partition of Land
Submission: as posted in MS Teams
Solve the following problems. Write your solutions on the space provided and write
your final answer on the space provided. After finalizing your answer and solution, took an
image using your smartphones, cameras or scanners and upload it thru MS Teams under the
designated Learning Tasks. You can use spreadsheets or CAD on your submission.
Name ___________________________________ Student No._______________ Yr/Sec ______
1. Given the description of the lot
a. Make a sketch of the lot
b. Compute the area of the lot
c. A dividing line is drawn from corner 5 to midpoint of line 2-3. Determine the
bearing and length of the dividing line
Line/Course Bearing Length Latitude Departure
1-2 S 47o 49’W 30.48 -20.47 -22.59
2-3 N 28o 16’W 111.37 +98.09 -52.73
3-4 N 79o 21’E 29.09 +5.38 +28.59
4-5 S 63o 26’E 59.68 -26.69 +53.38
5-1 S 06o 44’W 56.70 -56.31 -6.65
2. A parcel of land, with boundaries as described shown below is to be subdivided into two
equal lots. The dividing line is to pass through point X at midpoint of line 5-1 and through a
point Y along line 2-3. Determine the following
a. Total area of the lot
b. Determine the length of dividing line XY
c. Determine the bearing of XY
Line/Course Bearing Length(m) Latitude Departure
1-2 N 15o 30’E 60.00
2-3 S 82o 23’E 72.69
3-4 S 17o 20’E 44.83
4-5 S 70o 36’W 56.45
5-1 N 74o 30’W 50.00

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Module 3 Fund of Surveying 2 Partition of Land 1st 22-23.pdf

  • 1. FUNDAMENTALS OF SURVEYING 2 Self-Pace Module Module 3 PARTITION OF LAND (SUBDIVISION OF LAND) Topics 1.Dividing an Area Into Two Parts by a Line Between Two Points 2. Dividing an Area by A Line Running Through A Point in a Given Direction 3. To Cut off a Required Area by a Line through a Given Point 4. To Cut of a Required Area by a Line Running in a Given Direction Overview: This module will presents computations common cases encountered in partition and subdivision of land. Duration: Week 9-10 (2 weeks) Targeting Learning Outcomes Course Intended Learning Outcomes -Compute for the technical data of subdivided land - Subdivide the land by given line or required area Essential Questions Why does engineer or surveyor needs to know the process of subdividing the land Learning Targets At the end of this module, you should be able to learn how to subdivide lots thru given line or required area Reference and Credits: Elementary Surveying, by Ghilani and Wolf Elementary Surveying by La Putt Introduction The subdivision of land is a usual task undertaken by surveyors and engineers in property surveys. When tracts of land are sold or inherited it is often necessary to divide it into smaller parcels or into areas having certain proportions to each other. The process of subdivision may require the application of the principles of geometry and trigonometry or use of special techniques in computations or engineering software (CAD, GE Survey, Spreadsheets etc). For various cases in subdividing land, a resurvey is conducted, the latitudes and departures are determined, the surveyed traversed is adjusted and the areas are computed. When computing for subdivision of land, the adjusted latitudes and departures are used.
  • 2. CASE 1. Dividing an Area into Two Parts by a Line Between Two Points Example: Given the following data of tract of land, determine the area of a line running from F to C and calculate the length and bearing of line FC Course Adj Latitude Adjusted Departure AB 490.71 47.27 BC 587.12 608.89 CD -327.41 786.78 DE -1002.76 218.32 EF -122.67 -1116.62 FA 375.01 -544.64 ∑lat =0 ∑dep=0 A F B C D E
  • 3. Solution: 1. Determine the area of the whole close traverse Course Adj Latitude Adjusted Departure DMD Double Area (DMD x Adj Lat.) AB 490.71 47.27 47.27 23,195.86 BC 587.12 608.89 703.43 412,997.82 CD -327.41 786.78 2099.1 -687,266.33 DE -1002.8 218.32 3104.2 -3,112,767.59 EF -122.67 -1116.62 2205.9 -270,597.75 FA 375.01 -544.64 544.64 204,245.45 0 0 -3,430,192.55 AREA = -1,715,096.27 or -171.51 Hectares 2. Determine the length and bearing of dividing line FC (consider west section FABC) A F B C
  • 4. Course Adj Latitude Adjusted Departure AB 490.71 47.27 BC 587.12 608.89 FA 375.01 -544.64 Summation 1452.84 111.52 therefore length of line FC 1457.11 m Bearing of Line FC (tan-1 ∑dep/∑lat) 0.076609773 4.389417 S 4o 23' W Ans. 3. Compute for the area of FABC Course Adj Latitude Adjusted Departure DMD Double Area (DMD x Adj Lat.) AB 490.71 47.27 47.27 23,195.86 BC 587.12 608.89 703.43 412,997.82 CF -1452.8 -111.52 1200.8 -1,744,570.27 FA 375.01 -544.64 544.64 204,245.45 0 0 -1,104,131.14 AREA FABC = -552,065.57 sq.m. or -55.21 Hectares Ans
  • 5. 4. Compute bearing and length bearing of line CF using west portion CDEF Course Adj Latitude Adjusted Departure CD -327.41 786.78 DE -1002.76 218.32 EF -122.67 -1116.62 Summation -1452.84 -111.52 therefore length of line FC 1457.11 m Bearing of Line FC (tan-1 ∑dep/∑lat) 0.076609773 4.389417 N 4o 23' E Ans. F C D E
  • 6. 5. Compute for the area of CDEF Course Adj Latitude Adjusted Departure DMD Double Area (DMD x Adj Lat.) CD -327.41 786.78 786.78 -257,599.64 DE -1002.76 218.32 1791.88 -1,796,825.59 EF -122.67 -1116.62 893.58 -109,615.46 FC 1452.84 111.52 -111.52 -162,020.72 0 0 -2,326,061.40 AREA CDEF = -1,163,030.70 sq.m. or -116.30 Hectares Ans 6. Check the area of ABCDEF to sum of area CDEF and area ABCF AREA ABCDEF = 1,715,096.27 AREA ABCF= 552,065.57 sq.m AREA CDEF = 1,163,030.70 sq.m 1,715,096.27 sq.m. check!
  • 7. CASE 2. Dividing a Tract of Land by a Line Running in a Given Direction Example: Given the following data of tract of land, find the area of each of the two parts into which the tract is divided by a line through A with bearing of N 75o30’ E. Course Adj Latitude Adjusted Departure AB 490.71 47.27 BC 587.12 608.89 CD -327.41 786.78 DE -1002.76 218.32 EF -122.67 -1116.62 FA 375.01 -544.64 ∑lat =0 ∑dep=0 A F B C D E P
  • 8. Solution: 1. Determine the area of the whole close traverse Course Adj Latitude Adjusted Departure DMD Double Area (DMD x Adj Lat.) AB 490.71 47.27 47.27 23,195.86 BC 587.12 608.89 703.43 412,997.82 CD -327.41 786.78 2099.1 -687,266.33 DE -1002.8 218.32 3104.2 -3,112,767.59 EF -122.67 -1116.62 2205.9 -270,597.75 FA 375.01 -544.64 544.64 204,245.45 0 0 -3,430,192.55 AREA = -1,715,096.27 or -171.51 Hectares 2. Make a trial line AE, determine the length and bearing of line EA and area of AEF Course Adj. Latitude Adj. Departure EF -122.67 -1116.62 FA 375.01 -544.64 ∑ 252.34 -1661.26 therefore length of AE = 1680.32 m Bearing of Line AE (tan-1 ∑dep/∑lat) -1.42005 -81.36298 S 81o 22'E Ans Course Adj. Latitude Adj. Departur e DMD Double Area (DMD x Adj Lat.) EF -122.67 -1116.6 -1117 136,975.78 FA 375.01 -544.64 -2778 -1,041,732.78 EA -252.34 1661.26 -1661 419,202.35 ∑ 0 0 -485,554.66 AREA EFA = -242,777.33 or -24.28 Hectares ****We will use CAD for the other computation/solution or you can refer to solutions in Elementary Surveying by La Putt pp 503-506*****
  • 9. Learning Tasks No. 3: Problems Sets in Partition of Land Submission: as posted in MS Teams Solve the following problems. Write your solutions on the space provided and write your final answer on the space provided. After finalizing your answer and solution, took an image using your smartphones, cameras or scanners and upload it thru MS Teams under the designated Learning Tasks. You can use spreadsheets or CAD on your submission. Name ___________________________________ Student No._______________ Yr/Sec ______ 1. Given the description of the lot a. Make a sketch of the lot b. Compute the area of the lot c. A dividing line is drawn from corner 5 to midpoint of line 2-3. Determine the bearing and length of the dividing line Line/Course Bearing Length Latitude Departure 1-2 S 47o 49’W 30.48 -20.47 -22.59 2-3 N 28o 16’W 111.37 +98.09 -52.73 3-4 N 79o 21’E 29.09 +5.38 +28.59 4-5 S 63o 26’E 59.68 -26.69 +53.38 5-1 S 06o 44’W 56.70 -56.31 -6.65
  • 10.
  • 11. 2. A parcel of land, with boundaries as described shown below is to be subdivided into two equal lots. The dividing line is to pass through point X at midpoint of line 5-1 and through a point Y along line 2-3. Determine the following a. Total area of the lot b. Determine the length of dividing line XY c. Determine the bearing of XY Line/Course Bearing Length(m) Latitude Departure 1-2 N 15o 30’E 60.00 2-3 S 82o 23’E 72.69 3-4 S 17o 20’E 44.83 4-5 S 70o 36’W 56.45 5-1 N 74o 30’W 50.00